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Lewis Structures & Polyatomic Ions — Practice Test

30 multiple-choice + 2 free-response = 32 questions · valence electrons · bonds & bond order · the 4-step method · polyatomic ions · formal charge & resonance

Closed book. Keep scrap paper handy and sketch each structure before you answer. Aim for about 35 minutes. Answer everything, then press Submit at the bottom to see your score, the correct answers and an explanation for each one.

Part A — Multiple choice

1Valence Electrons

How many valence electrons does a nitrogen atom have?

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B) 5. N is in group 15, so it has 5 valence electrons (last digit of the group number).

2Valence Electrons

What is the total number of valence electrons in CH₂O (formaldehyde)?

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D) 12. C 4 + H 2 × 1 + O 6 = 12.

3Valence Electrons

Which atom can NEVER be the central atom in a Lewis structure?

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A) H. Hydrogen can form only one bond, so it is always on the outside (F is the same).

4Valence Electrons

According to the octet rule, how many electrons does a hydrogen atom need around it?

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C) 2. Hydrogen follows the duet rule: 2 electrons, like helium.

5Valence Electrons

In a neutral molecule, how many bonds does an oxygen atom usually form?

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D) 2. O has 6 valence electrons and is 2 short of an octet, so it forms 2 bonds (and keeps 2 lone pairs).

6Bonds & Bond Order

What is a lone pair?

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B) A pair of electrons that belongs to one atom and is not involved in bonding. A shared pair is a bonding pair; a pair held by only one atom is a lone pair.

7Bonds & Bond Order

How many electrons are shared in a triple bond?

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A) 6. 3 shared pairs × 2 electrons = 6 electrons.

8Bonds & Bond Order

What is the bond order of the bond in N₂?

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D) 3. N₂ is N≡N, a triple bond, so the bond order is 3.

9Bonds & Bond Order

Which carbon–carbon bond is the SHORTEST?

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C) C≡C. Higher bond order means a shorter bond: C≡C 1.203 Å < C=C 1.339 Å < C–C 1.535 Å.

10Bonds & Bond Order

Which bond needs the MOST energy to break?

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A) N≡N. More shared pairs make the bond stronger, so the triple bond is strongest.

11The 4-Step Method

In the Lewis structure of CO₂, which atom is central?

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B) C. C is less electronegative than O (2.5 vs 3.5) and forms the most bonds, so it goes in the middle: O=C=O.

12The 4-Step Method

Drawing CO₂: after step 3, each O has an octet but C has only 4 electrons and there are none left. What is the next step?

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D) Move one lone pair from each O into a double bond with C. Step 4: move lone pairs into multiple bonds. This never adds electrons; it just shares them, giving O=C=O.

13The 4-Step Method

How many lone pairs are on the central N atom in NH₃?

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B) 1. 8 electrons total: 3 N–H bonds use 6, and the last 2 form one lone pair on N.

14The 4-Step Method

How many lone pairs are on the O atom in H₂O?

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C) 2. 8 electrons: 2 O–H bonds use 4, and the remaining 4 are 2 lone pairs on O.

15The 4-Step Method

Which is the correct Lewis structure of HCN?

graph for question 15
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A) A. A has 10 electrons and every atom has an octet (H has 2). B uses 12 electrons (too many). C leaves C with only 6. D has the wrong skeleton: C, the less electronegative atom, should be central.

16The 4-Step Method

In formaldehyde (CH₂O), how many electrons are shared between C and O?

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C) 4. CH₂O has a C=O double bond: 2 shared pairs = 4 electrons.

17Polyatomic Ions

What is the total number of valence electrons in NH₄⁺?

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D) 8. 5 + 4(1) = 9, then subtract 1 for the + charge = 8.

18Polyatomic Ions

What is the total number of valence electrons in CO₃²⁻?

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B) 24. 4 + 3(6) = 22, then add 2 for the 2− charge = 24.

19Polyatomic Ions

What is the total number of valence electrons in SO₄²⁻?

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C) 32. 6 + 4(6) = 30, then add 2 for the 2− charge = 32.

20Polyatomic Ions

How is the charge of a polyatomic ion shown on its Lewis structure?

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D) Square brackets around the whole structure, with the charge outside at the top right. The charge belongs to the whole ion, so brackets go around everything and the charge is written outside.

21Polyatomic Ions

Which is the correct Lewis structure of the hydroxide ion, OH⁻?

graph for question 21
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B) B. OH⁻ has 6 + 1 + 1 = 8 electrons: one O–H bond and 3 lone pairs on O, in brackets with a − charge. A is missing an electron pair and the charge; C gives H a double bond; D puts 10 electrons around O.

22Polyatomic Ions

In the nitrite ion, NO₂⁻, how many lone pairs are on the central N atom?

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B) 1. 18 electrons: after the skeleton and filling both O, 2 electrons are left over and go on N as one lone pair. Then one O lone pair makes N=O.

23Polyatomic Ions

In ONE Lewis structure of nitrate (NO₃⁻), how many N=O double bonds are there?

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A) 1. 24 electrons give one N=O and two N–O bonds. (There are three such structures: resonance.)

24Formal Charge & Resonance

What is the formal charge on N in NH₄⁺?

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C) +1. FC = V − L − (bonds) = 5 − 0 − 4 = +1, which matches the ion's charge.

25Formal Charge & Resonance

In a nitrate (NO₃⁻) Lewis structure, what is the formal charge on each single-bonded O?

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A) −1. O has 3 lone pairs (6 electrons) and 1 bond: 6 − 6 − 1 = −1.

26Formal Charge & Resonance

What are resonance structures?

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C) Valid Lewis structures that differ only in where the electrons (double bonds) are placed. The atoms stay in the same places; only the position of the double bond (electrons) changes. They are joined by ↔.

27Formal Charge & Resonance

Both O=C=O and O≡C–O give every atom an octet. Why is O=C=O the better structure?

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B) Its formal charges are all zero. O≡C–O puts +1 and −1 on the O atoms. The best structure keeps formal charges closest to zero.

28Formal Charge & Resonance

Experiments show that in the real nitrate ion, the three N–O bonds are…

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D) all identical, in between a single and a double bond. The real ion is a blend of the 3 resonance structures, so all three bonds are equal (bond order 1⅓).

29Formal Charge & Resonance

The formal charges on all the atoms in a Lewis structure must add up to…

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A) the overall charge of the molecule or ion. For a neutral molecule the sum is 0; for SO₄²⁻ it is −2, and so on.

30Octet Exceptions

Which molecule has an INCOMPLETE octet on its central atom?

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B) BF₃. B has only 3 valence electrons; with 3 bonds it has just 6 electrons around it.

Part B — Free response (show your work)

31Polyatomic Ions · free response

Draw the Lewis structure of the sulfite ion, SO₃²⁻. Show all 4 steps, and give the formal charge on every atom.

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  • Step 1: 6 + 3(6) + 2 = 26 valence electrons.
  • Step 2: S is central (less electronegative than O). Draw 3 S–O single bonds: 6 electrons used, 20 left. Draw brackets with 2− outside.
  • Step 3: each O gets 3 lone pairs (18 electrons), leaving 2. Those go on S as 1 lone pair.
  • Step 4: S has 3 bonds + 1 lone pair = 8, and each O has 8. Nothing to move.
  • Formal charges: S = 6 − 2 − 3 = +1; each O = 6 − 6 − 1 = −1. Sum = +1 − 3 = −2, matching the charge.
32Formal Charge & Resonance · free response

Draw ALL the resonance structures of the carbonate ion, CO₃²⁻, and explain what the real ion looks like.

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  • Step 1: 4 + 3(6) + 2 = 24 valence electrons.
  • Steps 2–3: C in the centre with 3 single bonds (6 e⁻), then 3 lone pairs on each O (18 e⁻), so 0 left. C has only 6 electrons.
  • Step 4: move one lone pair from one O into a C=O double bond. C now has 8. That O has 2 lone pairs; the other two have 3 each (formal charge −1 each).
  • The double bond can go to any of the 3 O atoms, giving 3 resonance structures joined by ↔, all in brackets with 2−.
  • The real ion is a blend: all three C–O bonds are identical, between a single and a double bond (bond order 1⅓).