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MathOct 4, 2026 · Midterm review
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Math Midterm Review — Algebra, Quadratics and Statistics

One note for the whole midterm. Built from Session M1 (exponents to quadratic factorization), Session M2 (data and statistics), the Statistics Test Review and the Hypothesis Testing note, plus a new section on quadratic equations (section 4).

How to use it (45 minutes): 10 min sections 1–3 (recall) · 20 min section 4 (quadratics, new) · 10 min section 5 (statistics) · 5 min section 6 (mixed check).


1. Laws of exponents

For a,b≠0a, b \neq 0:

Law Rule Example
Product am⋅an=am+na^m \cdot a^n = a^{m+n} 23⋅24=27=1282^3 \cdot 2^4 = 2^7 = 128
Quotient am÷an=am−na^m \div a^n = a^{m-n} 56÷54=52=255^6 \div 5^4 = 5^2 = 25
Power of a power (am)n=amn(a^m)^n = a^{mn} (32)3=36=729(3^2)^3 = 3^6 = 729
Power of a product (ab)m=ambm(ab)^m = a^m b^m (2x)3=8x3(2x)^3 = 8x^3
Power of a quotient (ab)m=ambm\left(\frac{a}{b}\right)^m = \frac{a^m}{b^m} (23)2=49\left(\frac{2}{3}\right)^2 = \frac{4}{9}
Zero exponent a0=1a^0 = 1 70=17^0 = 1
Negative exponent a−n=1ana^{-n} = \frac{1}{a^n} 2−3=182^{-3} = \frac{1}{8}
Rational exponent am/n=(an)ma^{m/n} = \left(\sqrt[n]{a}\right)^m 82/3=(83)2=48^{2/3} = (\sqrt[3]{8})^2 = 4

Why a0=1a^0 = 1: an÷an=an−n=a0a^n \div a^n = a^{n-n} = a^0, and any nonzero number divided by itself is 1.

Same base, equal powers: if ax=aya^x = a^y (with a>0a > 0, a≠1a \neq 1), then x=yx = y. Example: 2x+1=32=25⇒x=42^{x+1} = 32 = 2^5 \Rightarrow x = 4.

Common mistakes: (a+b)2≠a2+b2(a+b)^2 \neq a^2 + b^2 · −32=−9-3^2 = -9 but (−3)2=9(-3)^2 = 9 · 2x−1=2x2x^{-1} = \frac{2}{x}, not 12x\frac{1}{2x}.

2. Polynomials, identities and the two theorems

Degree = highest power of the variable. Linear (1), quadratic (2), cubic (3).

Identities (memorize):

(a+b)2=a2+2ab+b2(a−b)2=a2−2ab+b2a2−b2=(a+b)(a−b)(a+b)^2 = a^2 + 2ab + b^2 \qquad (a-b)^2 = a^2 - 2ab + b^2 \qquad a^2 - b^2 = (a+b)(a-b)

(x+a)(x+b)=x2+(a+b)x+ab(x+a)(x+b) = x^2 + (a+b)x + ab

a3+b3=(a+b)(a2−ab+b2)a3−b3=(a−b)(a2+ab+b2)a^3 + b^3 = (a+b)(a^2 - ab + b^2) \qquad a^3 - b^3 = (a-b)(a^2 + ab + b^2)

Remainder Theorem. When a polynomial p(x)p(x) is divided by (x−a)(x - a), the remainder is p(a)p(a).

Factor Theorem. (x−a)(x - a) is a factor of p(x)p(x) exactly when p(a)=0p(a) = 0.

Example. Is (x−2)(x-2) a factor of p(x)=x3−3x2+4p(x) = x^3 - 3x^2 + 4? p(2)=8−12+4=0p(2) = 8 - 12 + 4 = 0, so yes.

3. Factoring — pick the method in this order

  1. Common factor first: 6x2+9x=3x(2x+3)6x^2 + 9x = 3x(2x + 3).
  2. Two terms: difference of squares a2−b2=(a+b)(a−b)a^2 - b^2 = (a+b)(a-b). Example: 4x2−25=(2x+5)(2x−5)4x^2 - 25 = (2x+5)(2x-5). A sum of squares a2+b2a^2 + b^2 does not factor over the real numbers.
  3. Three terms ax2+bx+cax^2 + bx + c: split the middle term. Find two numbers with product acac and sum bb, rewrite bxbx with them, then factor by grouping.
  4. Four terms: group in pairs.

Why splitting works: (px+q)(rx+s)=prx2+(ps+qr)x+qs(px + q)(rx + s) = pr\,x^2 + (ps + qr)x + qs. The two middle pieces psps and qrqr add to bb and multiply to (pr)(qs)=ac(pr)(qs) = ac.

Example (a=1a = 1). x2+7x+12x^2 + 7x + 12: product 12, sum 7 → 3 and 4. Answer (x+3)(x+4)(x+3)(x+4).

Example (a≠1a \neq 1). 6x2+11x−106x^2 + 11x - 10: product −60-60, sum 1111 → 1515 and −4-4.

6x2+15x−4x−10=3x(2x+5)−2(2x+5)=(3x−2)(2x+5)6x^2 + 15x - 4x - 10 = 3x(2x + 5) - 2(2x + 5) = (3x - 2)(2x + 5)

Sign guide: c>0c > 0 → both numbers have the sign of bb. c<0c < 0 → opposite signs; the larger one has the sign of bb.

Always check by multiplying back.

4. Quadratic equations (new)

Standard form: ax2+bx+c=0ax^2 + bx + c = 0, with a≠0a \neq 0. The solutions are also called roots or zeros; on a graph they are the x-intercepts.

4.1 Four ways to solve

(1) Factoring + Zero Product Property. If A⋅B=0A \cdot B = 0 then A=0A = 0 or B=0B = 0. One side must be 0 first.

x2−5x=14⇒x2−5x−14=0⇒(x−7)(x+2)=0⇒x=7 or x=−2x^2 - 5x = 14 \;\Rightarrow\; x^2 - 5x - 14 = 0 \;\Rightarrow\; (x - 7)(x + 2) = 0 \;\Rightarrow\; x = 7 \text{ or } x = -2

(2) Square roots (when there is no xx term). Remember the ±\pm.

3x2−48=0⇒x2=16⇒x=±4(x−1)2=9⇒x−1=±3⇒x=4 or −23x^2 - 48 = 0 \;\Rightarrow\; x^2 = 16 \;\Rightarrow\; x = \pm 4 \qquad\qquad (x - 1)^2 = 9 \;\Rightarrow\; x - 1 = \pm 3 \;\Rightarrow\; x = 4 \text{ or } -2

(3) Completing the square. Add (b2)2\left(\frac{b}{2}\right)^2 to both sides (when a=1a = 1).

x2+6x−7=0⇒x2+6x=7⇒x2+6x+9=16⇒(x+3)2=16⇒x=−3±4x^2 + 6x - 7 = 0 \;\Rightarrow\; x^2 + 6x = 7 \;\Rightarrow\; x^2 + 6x + 9 = 16 \;\Rightarrow\; (x + 3)^2 = 16 \;\Rightarrow\; x = -3 \pm 4

So x=1x = 1 or x=−7x = -7.

(4) Quadratic formula. Works for every quadratic.

x=−b±b2−4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

4.2 Derivation of the quadratic formula (completing the square on the general equation)

ax2+bx+c=0ax^2 + bx + c = 0

Divide by aa and move the constant:

x2+bax=−cax^2 + \frac{b}{a}x = -\frac{c}{a}

Add (b2a)2\left(\frac{b}{2a}\right)^2 to both sides:

x2+bax+b24a2=b24a2−ca⇒(x+b2a)2=b2−4ac4a2x^2 + \frac{b}{a}x + \frac{b^2}{4a^2} = \frac{b^2}{4a^2} - \frac{c}{a} \;\Rightarrow\; \left(x + \frac{b}{2a}\right)^2 = \frac{b^2 - 4ac}{4a^2}

Take square roots and solve for xx:

x+b2a=±b2−4ac2a⇒x=−b±b2−4ac2ax + \frac{b}{2a} = \pm\frac{\sqrt{b^2 - 4ac}}{2a} \;\Rightarrow\; x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

Example. 2x2−3x−5=02x^2 - 3x - 5 = 0: a=2a = 2, b=−3b = -3, c=−5c = -5.

b2−4ac=9+40=49x=3±74⇒x=52 or x=−1b^2 - 4ac = 9 + 40 = 49 \qquad x = \frac{3 \pm 7}{4} \;\Rightarrow\; x = \frac{5}{2} \text{ or } x = -1

4.3 The discriminant D=b2−4acD = b^2 - 4ac

Discriminant Roots Graph
D>0D > 0 two different real roots (rational if DD is a perfect square) crosses the x-axis twice
D=0D = 0 one repeated real root, x=−b2ax = -\frac{b}{2a} touches the x-axis at the vertex
D<0D < 0 no real roots (two complex roots) never meets the x-axis

Example. x2+4x+5=0x^2 + 4x + 5 = 0: D=16−20=−4<0D = 16 - 20 = -4 < 0, no real roots. With i=−1i = \sqrt{-1} (so i2=−1i^2 = -1): x=−4±2i2=−2±ix = \frac{-4 \pm 2i}{2} = -2 \pm i.

4.4 Sum and product of the roots

If the roots are r1r_1 and r2r_2:

r1+r2=−bar1r2=car_1 + r_2 = -\frac{b}{a} \qquad r_1 r_2 = \frac{c}{a}

Why: expand a(x−r1)(x−r2)a(x - r_1)(x - r_2) to get ax2−a(r1+r2)x+ar1r2ax^2 - a(r_1 + r_2)x + a\,r_1 r_2, then match the coefficients with ax2+bx+cax^2 + bx + c.

A quadratic with roots r1,r2r_1, r_2: x2−(sum)x+(product)=0x^2 - (\text{sum})x + (\text{product}) = 0. Roots 3 and −5-5: x2+2x−15=0x^2 + 2x - 15 = 0.

4.5 Graph of y=ax2+bx+cy = ax^2 + bx + c (a parabola)

Feature How to find it
Direction a>0a > 0 opens up (minimum) · a<0a < 0 opens down (maximum)
Axis of symmetry x=−b2ax = -\frac{b}{2a}
Vertex x=−b2ax = -\frac{b}{2a}, then substitute to get yy
y-intercept (0,c)(0, c)
x-intercepts solve ax2+bx+c=0ax^2 + bx + c = 0

Three forms:

Example. y=x2−4x−5y = x^2 - 4x - 5. Axis x=42=2x = \frac{4}{2} = 2. Vertex y=4−8−5=−9y = 4 - 8 - 5 = -9, so vertex (2,−9)(2, -9), a minimum. Vertex form y=(x−2)2−9y = (x - 2)^2 - 9. Factored y=(x−5)(x+1)y = (x - 5)(x + 1), x-intercepts 55 and −1-1. y-intercept (0,−5)(0, -5).

4.6 Word problem pattern (US units)

Height of an object thrown upward: h(t)=−16t2+v0t+h0h(t) = -16t^2 + v_0 t + h_0 (feet, seconds).

Example. A ball is thrown up at 48 ft/s from a height of 64 ft: h=−16t2+48t+64h = -16t^2 + 48t + 64.

4.7 Hidden quadratics (from M1)

Substitute to make it a quadratic. 4x−6⋅2x+8=04^x - 6 \cdot 2^x + 8 = 0: let u=2xu = 2^x, so u2−6u+8=0u^2 - 6u + 8 = 0, (u−2)(u−4)=0(u - 2)(u - 4) = 0, 2x=22^x = 2 or 44, so x=1x = 1 or x=2x = 2.

5. Statistics

5.1 Collecting data

Term Meaning
Population / sample the whole group / the part actually measured
Parameter / statistic a number describing a population (μ\mu, σ\sigma) / describing a sample (x‾\bar{x})
Bias a method that systematically favors some outcomes

Sampling methods: simple random (every member equally likely) · systematic (every kkth) · stratified (random sample from every group) · cluster (all members of a few random groups) · convenience and self-selected (both biased).

Ways to collect data: survey · observational study (watch, no treatment; shows association only) · experiment (treatment is assigned at random; the only method that can show cause) · simulation.

Bias to look for: undercoverage, non-response, leading question wording, self-selection.

5.2 Center

5.3 Spread

Check. Scores 6, 7, 7, 8, 8, 8, 8, 9, 9, 10: mean 8; squared distances add to 12; σ=1.2≈1.10\sigma = \sqrt{1.2} \approx 1.10.

5.4 Graphs

Bar graph: categories, gaps between bars. Histogram: continuous classes, no gaps; with unequal class widths plot adjusted frequency =frequencyclass width×smallest width= \frac{\text{frequency}}{\text{class width}} \times \text{smallest width}. Frequency polygon: join the class marks.

5.5 Normal distribution

Bell-shaped, symmetric about the mean.

Example. μ=70\mu = 70, σ=5\sigma = 5. What percent is between 65 and 80? 65 is −1σ-1\sigma, 80 is +2σ+2\sigma: 34%+34%+13.5%=81.5%34\% + 34\% + 13.5\% = 81.5\%. And x=82x = 82 gives z=82−705=2.4z = \frac{82 - 70}{5} = 2.4.

5.6 Margin of error and hypothesis testing

Rule: if the observed result (or one more extreme) shows up in α\alpha or less of the simulated samples, reject the null hypothesis. Otherwise do not reject (this does not prove the claim).

Example. 36 heads in 50 flips appeared in 0 of 200 fair-coin simulations (0% ≤ 5%): reject “the coin is fair”. 29 heads appeared in 39 of 200 (19.5% > 5%): do not reject.

6. Mixed check (answers below)

  1. Simplify (2x3)2⋅x−44x\frac{(2x^3)^2 \cdot x^{-4}}{4x}.
  2. Evaluate 272/327^{2/3}.
  3. Factor 3x2−123x^2 - 12.
  4. Factor 2x2+7x+32x^2 + 7x + 3.
  5. Solve x2−9x+20=0x^2 - 9x + 20 = 0.
  6. Solve x2+4x−1=0x^2 + 4x - 1 = 0 (exact form).
  7. How many real roots does 3x2−2x+5=03x^2 - 2x + 5 = 0 have?
  8. Find the vertex of y=−2x2+8x−3y = -2x^2 + 8x - 3. Is it a maximum or a minimum?
  9. Is (x+1)(x + 1) a factor of x3+2x2−x−2x^3 + 2x^2 - x - 2?
  10. Test scores are normal with μ=500\mu = 500, σ=100\sigma = 100. Find the z-score of 650 and the percent of scores between 400 and 600.
  11. A poll of 900 people finds 60% in favor. Give the margin of error and the interval.
  12. A result occurred in 8 of 200 simulations. At α=0.05\alpha = 0.05, reject or not?

Answers, step by step

  1. (2x3)2=4x6(2x^3)^2 = 4x^6; 4x6⋅x−4=4x24x^6 \cdot x^{-4} = 4x^2; 4x24x=x\frac{4x^2}{4x} = x.
  2. 273=3\sqrt[3]{27} = 3; 32=93^2 = 9.
  3. 3(x2−4)=3(x+2)(x−2)3(x^2 - 4) = 3(x + 2)(x - 2).
  4. Product 6, sum 7 → 6 and 1: 2x2+6x+x+32x^2 + 6x + x + 3 =2x(x+3)+1(x+3)= 2x(x + 3) + 1(x + 3) =(2x+1)(x+3)= (2x + 1)(x + 3).
  5. (x−4)(x−5)=0(x - 4)(x - 5) = 0, so x=4x = 4 or x=5x = 5.
  6. x=−4±16+42=−4±252=−2±5x = \frac{-4 \pm \sqrt{16 + 4}}{2} = \frac{-4 \pm 2\sqrt{5}}{2} = -2 \pm \sqrt{5}.
  7. D=4−60=−56<0D = 4 - 60 = -56 < 0: no real roots.
  8. x=−82(−2)=2x = -\frac{8}{2(-2)} = 2; y=−8+16−3=5y = -8 + 16 - 3 = 5. Vertex (2,5)(2, 5), a maximum because a<0a < 0.
  9. p(−1)=−1+2+1−2=0p(-1) = -1 + 2 + 1 - 2 = 0: yes.
  10. z=650−500100=1.5z = \frac{650 - 500}{100} = 1.5. 400 to 600 is μ±σ\mu \pm \sigma: 68%.
  11. 1900=130≈0.033\frac{1}{\sqrt{900}} = \frac{1}{30} \approx 0.033, so about ±3.3%\pm 3.3\%: 56.7% to 63.3%.
  12. 8200=4%≤5%\frac{8}{200} = 4\% \leq 5\%: reject the null hypothesis.

Notes for next session